COORDENADAS:

P1= (X1,Y1)
P2= (X2,Y2)

P1P2= (X1-X2)(X1-X2) +(Y1-Y2)(Y1-Y2)
C= (a)(a)+(b)(b)
p1p2= (6-2)(6-2)+(8-4)(8-4)
p1p2= 16+16
p1p2= 32
p1p2= 5.65



Demostrar que el triangulo abc cfon vertice A=(3,3) B=(-3,-3) y C=(-33, 33 ) es equilatero.





AB= (-3,-3)(-3,-3)+(-3,-3)(-3,-3)
AB = 8.48

BC= (-33+3)(-33+3)+(33+3)(33+3)
BC= 8.48

CA= (3+33)(3+33)+(3-33)(3-33)
CA=8.48